Physics

Purpose: the purpose of this experiment is to investigate the two alter conditions necessary to reach equilibrium in an object. These two conditions be that the net personnel office must add up to nobody and the torque should add up to zero as well. Equipment: prod edge clamps, Balance support, Meter stick and Masses. method: we started by balancing a meter stick on the ratio support. Next we used 2 musses one on each side to balance the masses 3 multiplication at different distances form the place. Next we used 3 masses and placing two at different distances form the magnetic core on one side of the meter stick from the center. We performed this 3 times as well. In order for the torque to elegant to middling zero and the meter stick to be balanced, the sum force times the total distance from the center has to be fair to middling on both sides of the meter stick. Results: M= .507 kg F1 = m1g (N)D1 (m)t = F1d1 (Nm)F2 = m2g (N)d2 (m)?2 = F2d2 (Nm) part Di fference 0.4905.415.204.981.21.206.9% 0.4905.40.1961.962.10.1960% 0.981.20.1961.962.10.1960% F1 = m1g (N)D1 (m)t = F1d1 (Nm)F2 = m2g (N)d2 (m)F3 (m)D3 (m) ?2 = F2d2 + F3d3 (Nm) part Difference 1.962.1225.240.4905.11 1.962.20.392.4905.22 1.962.30.589.4905.

351 Questions: 1.At the beginning of each experimental run, the velocities of both the pushcart and the reprieve mass were zero. a.What was the energising heftiness of the tangle? 0J b.What was the energising energy of the hanging mass? 0J 2.Consider the first amount that you do with only 25 grams attached to the string. a.What was the veloc ity of the cart by and by it moved a distan! ce h? .71 m/s b.When the cart/hanging mass scheme was moving with this velocity, what was the energizing energy of the cart? .128 J c.What was the kinetic energy of the hanging mass (hanger plus attached mass)? .006 J d.What was the change in the kinetic energy of cart/hanging mass system during this process? .134...If you indirect request to get a panoptic essay, order it on our website: BestEssayCheap.com

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